Engineering calculators

3 Phase Current Calculator

Updated Sep 27, 2026 By Infinity Calculator

Input Values

Supply voltage (volts). Choose L-L or L-N beside this field.
Voltage Input Type
L-N is converted internally: VLL = VLN × √3.
1 HP = 745.69987 W. Value is converted to watts before calculating.
PF
Dimensionless, 0.01 – 1.00. Default 0.85 (typical industrial assumption).
Sets the sign convention shown for reactive power Q.
All results are re-rendered in the selected current unit.

Results

Line Current (I)
84.91 A
Apparent Power (S)
58.82 kVA
Reactive Power (Q)
30.99 kVAR
Power per Phase
16.67 kW

Detailed Output

Three-phase balanced-load results for the entered voltage, power and power factor.
Quantity Value Unit

Step-by-Step Solution

Line Current vs. Power Factor

Power Triangle (P, Q, S)

Result Actions


Introduction

The 3 Phase Current Calculator finds the line current in a three-phase electrical system. Enter your voltage, power, and power factor, and it returns the current in amps.

Three-phase power is used widely in industry.2 Larger motors usually need it.1 To pick the right wire size, breaker, or fuse, you need to know the current. Working it out by hand takes time and is easy to get wrong. The calculator runs the same arithmetic every time, so a slipped decimal does not end up in your wire sizing.

It uses the standard formula: I = P ÷ (√3 × V × PF).1 You can enter voltage as line-to-line or line-to-neutral, and pick units like volts, kilovolts, watts, kilowatts, or horsepower. The results show line current, apparent power (kVA), reactive power (kVAR), power per phase, and the phase angle.

You also get a full step-by-step solution, a table of results, and two charts. One chart shows how current changes with power factor. The other shows the power triangle. Electricians, engineers, and students can follow the worked steps to check their own figures before planning a job.

How to use our 3 Phase Current Calculator

Enter your supply voltage, the load power, and the power factor. The calculator gives you the line current in amps, plus apparent power (kVA), reactive power (kVAR), power per phase, the phase angle, and a full step-by-step solution.

Voltage: Type the supply voltage of your three phase system, like 400 or 480. Then pick the unit next to the box: V, kV, or mV.

Voltage Input Type: Choose Line-to-Line (L-L) if your voltage is measured between two phases. Choose Line-to-Neutral (L-N) if it is measured from one phase to neutral. The tool changes L-N to L-L for you by multiplying by √3.

Power (Real Power, P): Type the real power of the load and pick the unit: W, kW, MW, or HP. Use HP for motors rated in horsepower, and the tool turns it into watts.

Power Factor (PF): Enter a number from 0.01 to 1.00. Use 1.00 for pure resistive loads like heaters.5 A typical induction motor runs at around 85% power factor, so about 0.85 suits most motors.2 Check the motor nameplate if you have it.

Load Type: Pick Lagging for inductive loads such as motors and transformers. Pick Leading for capacitive loads. This only sets the plus or minus sign shown for reactive power Q.

Current Output Unit & Precision: Choose how to show the answer: A, kA, or mA. Then choose how many decimal places you want, from 0 to 4.

Press Calculate to see your results, the data table, the charts, and the worked steps. Press Reset to go back to the sample values, or Print Results to save a copy.

What Is Three-Phase Current?

Three-phase power uses three live wires instead of one.1 Each wire carries an equal voltage, and the three waves are spaced 120°, or one-third of a cycle, apart.3 Because the waves take turns peaking, the total power flowing into the load stays constant, in a smooth, steady stream.1 That is why larger motors use three-phase power instead of single-phase power.1

Three-phase current is the amount of electricity, measured in amps (A), that flows through each line wire of that system. Knowing this number matters because wires, breakers, fuses, and contactors are all picked by amps. Guess too low and the wire overheats. Guess too high and you pay for copper you do not need.

The Formula

For a balanced three-phase load, line current is found with:

I = P ÷ (√3 × VLL × PF)1

  • I is the line current in amps
  • P is the real power in watts (1 kW = 1,000 W; 1 HP ≈ 0.7457 kW)1
  • √3 is about 1.732, the three-phase constant
  • VLL is the line-to-line voltage in volts
  • PF is the power factor, a number from 0.01 to 1.00

Line Voltage vs. Phase Voltage

Line-to-line (L-L) voltage is measured between any two hot wires.1 Line-to-neutral (L-N) voltage is measured from one hot wire to neutral.1 Line-to-line readings are 1.73 times line-to-neutral readings, so VLL = VLN × √3.1 That means a 400 V L-L system has about 230 V L-N, and a 208 V system has about 120 V. Always check which one you are reading before you plug it into the formula.

Why Power Factor Matters

Power factor tells you what part of the power the wires carry actually does useful work.3 Motors pull extra current to build the magnetic field in their windings, so their power factor is below 1.1 A load at 0.85 PF draws about 18% more current than the same load at 1.00 PF. Lower power factor means more amps for the same work, and that extra current wastes energy as heat in the wiring.2 A typical induction motor runs at around 85% power factor, so 0.85 is a common starting guess.2

Real, Reactive, and Apparent Power

Three kinds of power show up in AC systems:

  • Real power (P) in watts is the part that does work, like turning a shaft or making heat.3
  • Reactive power (Q) in VAR is the part that swings back and forth and does no work.3
  • Apparent power (S) in VA is the total the wires must carry, found by S = √3 × VLL × I.3

Together they form a right triangle, the power triangle, where S² = P² + Q².4 Power factor is the ratio of real power to apparent power: PF = P ÷ S.3 In an inductive load, the current lags the voltage, so its power factor is called lagging.3 In a capacitive load the current leads, so its power factor is leading.3 Capacitors can supply some of a motor's reactive power, which raises the power factor.1

Wye and Delta Loads

In a wye (star) connection, phase current equals line current.3 In a delta connection, each phase winding carries line current divided by √3.3 Total power is the same either way, but the current inside the windings is not, so check the wiring before sizing anything internal.3

A Quick Example

A 50 kW load on 400 V three-phase at 0.85 power factor:

I = 50,000 ÷ (1.732 × 400 × 0.85) = 50,000 ÷ 588.9 = 84.91 A

That load needs a breaker and wire rated above 84.91 A, with extra headroom for motor starting, ambient heat, and local code rules.

Good to Know

  • This math assumes a balanced load, meaning all three phases draw the same current.3
  • Large motors started straight across the line often draw six to eight times their normal operating current.2
  • Long cable runs add voltage drop. A lower voltage at a motor usually raises the current it needs to carry its load, so the real current can be higher than the plain formula shows.2
  • Motor nameplates list output horsepower at the shaft, not input watts.2 Divide by the motor's efficiency for a true input figure.1
  • Always follow the NEC, IEC, or your local wiring rules when picking wire and protection sizes.

Formulas used

Line Current (three-phase) 1
I = \frac{P}{\sqrt{3} \times V_{LL} \times PF}
Line-to-Line Voltage from Line-to-Neutral 3
V_{LL} = V_{LN} \times \sqrt{3}
Apparent Power 3
S = \sqrt{3} \times V_{LL} \times I
Phase Angle 3
\varphi = \arccos(PF)
Reactive Power 3
Q = S \sin\varphi
Power per Phase (balanced load) 3
P_{phase} = \frac{P}{3}
Phase Current in Delta Connection 3
I_{phase(\Delta)} = \frac{I}{\sqrt{3}}

Frequently asked questions

How many amps does a 10 HP three-phase motor draw at 480V?

About 12 to 14 amps. Here is the math:

  • 10 HP = 7,457 W of output power
  • At 90% efficiency, input power = 7,457 ÷ 0.90 = 8,286 W
  • I = 8,286 ÷ (1.732 × 480 × 0.85) = 11.7 A

Code tables list 14 A for a 10 HP motor at 460V, since they use safe average values. Always use the nameplate amps if you have them.

Why is 1.732 used in three-phase calculations?

1.732 is the square root of 3. The three voltage waves are spaced 120° apart.3 Because of that phase difference, the voltage between two lines is 1.73 times the voltage from one line to neutral, not 2 times.1

That is why line-to-line voltage is √3 × line-to-neutral voltage, and why √3 shows up in every three-phase power and current formula.3

How do you convert kVA to amps in a three-phase system?

Use this formula:

I = (kVA × 1,000) ÷ (√3 × VLL)3

Example: a 100 kVA transformer at 480V gives I = 100,000 ÷ (1.732 × 480) = 120 A.

Power factor is not used here. kVA is already the total the wires must carry.3

How do you convert three-phase amps back to kW?

Flip the current formula around:

kW = (1.732 × VLL × I × PF) ÷ 1,0002

Example: 85 A at 400V and 0.85 PF gives (1.732 × 400 × 85 × 0.85) ÷ 1,000 = 50 kW.

Skip the PF and you get kVA instead of kW.3

Why does a three-phase load draw less current than a single-phase load of the same size?

Because the power is shared across three wires instead of one. For the same voltage and power, three-phase current is about 42% lower.

  • Single-phase: I = P ÷ (V × PF)3
  • Three-phase: I = P ÷ (1.732 × V × PF)2

Lower current means smaller wires, less heat, and cheaper installs.6 That is one reason big loads use three-phase.

What power factor should I use if I don't know the load's power factor?

Use these common starting values:

  • 1.00 for heaters, ovens, and resistive loads5
  • 0.85 for general motor loads, since a typical induction motor runs at around 85% power factor2
  • 0.80 for small or lightly loaded motors
  • 0.95 or higher for drives and modern LED lighting

These are guesses. The motor or equipment nameplate gives the real number, and a power meter gives the true value under load.

Does the neutral wire carry current in a three-phase system?

In a perfectly balanced load, the three currents cancel and the neutral carries almost nothing.3

But real systems are rarely perfect. Neutral current shows up when:

  • The three phases carry different loads3
  • You have many single-phase loads on one phase
  • Electronic power controls and other nonlinear loads create harmonics7

Some harmonic currents add together in the neutral and can make it overheat, so never undersize it in a building with lots of electronics.7

How do you find the current in an unbalanced three-phase system?

The √3 formula only works for balanced loads.3 For unbalanced loads, work out each phase on its own:

Iphase = Pphase ÷ (VLN × PF)3

Do this for phase A, B, and C using each one's own power and voltage. Then size your wires and breaker for the highest phase current, not the average.

What size breaker do you need for a three-phase load?

For a continuous load, a common rule is breaker size = load current × 1.25, then round up to the next standard breaker.

Example: an 85 A load × 1.25 = 106 A, so you would use a 110 A or 125 A breaker.

Motors are different. Starting a motor straight across the line often draws six to eight times its normal operating current.2 So motor circuits use special sizing rules for the breaker and separate overload protection. Check the NEC, IEC, or your local code.

How do you measure three-phase current with a clamp meter?

Clamp around one conductor at a time. Read L1, then L2, then L3 and write down each value.

Clamping more than one wire gives a false reading. On a balanced load the three currents cancel, so clamping all three at once reads near zero.3 Compare the three readings: if one is far off from the others, your load is unbalanced or something is wrong.

What happens to the current if one phase is lost?

This is called single phasing, and it is hard on motors. The motor keeps spinning but the two remaining wires must carry all the load. Their current jumps to roughly 1.7 to 2 times normal.

The windings overheat fast and can burn out in minutes. This is why motors need phase-loss protection or proper overload relays.

Do you need to include motor efficiency when calculating current?

Yes. A motor nameplate lists horsepower as output power at the shaft, not the power it pulls from the line.2 The motor also burns some power as heat.

Divide output power by efficiency to get input power:

Input kW = (HP × 0.7457) ÷ efficiency1

A 20 HP motor at 91% efficiency pulls (20 × 0.7457) ÷ 0.91 = 14.914 ÷ 0.91 = 16.39 kW. Skip this step and your current will come out about 10% too low.


Sources

  1. Determining Electric Motor Load and Efficiency (DOE/GO-10097-517). U.S. Department of Energy. p. 3, Equations 1 and 2; p. 10, Electrical Glossary. Accessed September 27, 2026.
  2. Improving Motor and Drive System Performance: A Sourcebook for Industry (DOE/GO-102014-4356). U.S. Department of Energy. 2014;pp. 5, 9, 35, 43, 44, 49. Accessed September 27, 2026.
  3. DOE Fundamentals Handbook: Electrical Science, Volume 3 of 4 (DOE-HDBK-1011/3-92). U.S. Department of Energy. 1992;Module ES-09, pp. 1-4, 17-23. Accessed September 27, 2026.
  4. Kuphaldt TR. Electric Circuits II - Alternating Current, Section 11.2: True, Reactive, and Apparent Power. LibreTexts. The Power Triangle. Accessed September 27, 2026.
  5. Kuphaldt TR. Electric Circuits II - Alternating Current, Section 11.3: Calculating Power Factor. LibreTexts. Accessed September 27, 2026.
  6. Kuphaldt TR. Electric Circuits II - Alternating Current, Section 7.2: Three-phase Power Systems. LibreTexts. Accessed September 27, 2026.
  7. Kuphaldt TR. Electric Circuits II - Alternating Current, Section 7.7: Harmonics in Polyphase Power Systems. LibreTexts. Accessed September 27, 2026.